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Yahoo! Answers - Sol. of 14.8M of NH3. How many mL of sol should ...

Best Answer: M1V1=M2V2 14.8 * V1 = 0.25*100 V1 = 0.25*100/14.8 V1 = 1.689ml M1V1= M2V2 14.8*10 = M2*250 M2 = 14.8*10/250 M2 = 0.592M

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Yahoo! Canada Answers - A mole of X reacts at a constant pressure ...

Best Answer: Given data H0 = -75.0 kJ Pressure, P = 43.0 atm = 43 atm * 101325 Pa/1 atm = 4356975 Pa = 4356975 N / m2 Volume change, V = 2.0 L - 5.0 L = -3.0 L ...

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How do I make a 10 millimolar solution of HCl (in 1 Litre of Water ...

Thanks for your answer Dr Buzz.. I calculated that at 1st but I need the HCl amount in mL. So i suspect im meant to use the V1 x M1 = V2 x M2 equation..

Yahoo! Canada Answers - A mole of X reacts at a constant pressure ...

Best Answer: Given data H0 = -75.0 kJ Pressure, P = 43.0 atm = 43 atm * 101325 Pa/1 atm = 4356975 Pa = 4356975 N / m2 Volume change, V = 2.0 L - 5.0 L = -3.0 L ...

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A 20.00 mL sample of 0.009873 mol/L oxalic acid was titrated with potassium permanganate. If 32.33 mL of a KMnO4 solution was required to reach the pink end point ...